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Solution :

`l = 20 cm = 20 xx 10^(-2) m`, <br> `w = 10 cm = 10 xx 10 xx^(-2) m` <br> So, `a = lw = 0.02 m^(2)`, <br> `I = 5 A`, <br> `B = 0.2T` <br> (a) There is no force on the sides ab and cd but the force on the sides ad and be are apposite . So on the loop .<br> `tau = nia xx B = nia B sin 90^@` <br> `= 1 xx 5 xx 20 xx 10^(-2) xx 10 xx 10^(-2) xx 0.2` <br> `= 5 xx 20 xx 10 xx2 xx 10^(-6)` <br> `= 1000 xx 2 xx 10^(-6)` <br> `= 2 xx 10^(-2)` <br> `= 0.02 N m` <br> Paraller to the shorter side.**Magnetic Force**

**FLEMING'S LEFT HAND RULE**

**Right Hand Rule**

**MOTION OF CHARGED PARTICLE IN UNIFORM MAGNETIC FIELD WHEN V AND B ARE PARALLEL/ANTIPARALLEL)**

**MOTION OF CHARGED PARTICLE IN UNIFORM MAGNETIC FIELD WHEN V AND B ARE PERPENDICULAR)**

**MOTION OF CHARGED PARTICLE IN UNIFORM MAGNETIC FIELD WHEN V AND B ARE AT SOME ANGLE THAN 0, 90 AND 180**

**Magnetic Force On A Current Carrying Conductor**

**Magnetic Dipole Moment**

**Magnetic Dipole Moment In 3d**

**Magnetic Dipole In Uniform Magnetic Field**