# Aptitude | Simplification and Approximation | Question 10

b – [b -(a+b) – {b – (b – a+b)} + 2a] = ?**(A)** 2a**(B)** a+b**(C)** b-2a**(D)** 0**Answer:** **(D)****Explanation:** BODMAS rule

b – [b -(a+b) – {b – (2b – a)} + 2a]

b-[b-a-b-{-b+a}+2a]

b-[b-a-b-a+b+2a]

b-b=0

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