# Line slope calculator x+6y=33

**Straight line given by points A[3; 5] and B[9; 4]**

## Calculation:

**Slope-intercept form of line:**y = -0.1667x+5.5

**Canonical form of the line equation:**x+6y-33 = 0

**Parametric form of the line equation:**

x = 6t+3

y = -t+5 ; t ∈ R

**Slope:**m = -0.1667

**Slope angle of line: φ =**-9°27'44″ = -0.1651 rad

**X intercept:**x

_{0}= 33

**Y intercept:**y

_{0}= q = 5.5

**Distance line from the origin:**d

_{0}= 5.4252

**The length of the segment AB: |AB| =**6.0828

**Vector: AB =**(6; -1)

**Normal vector: n =**(1; 6)

**Midpoint of the segment AB: M =**[6; 4.5]

**Perpendicular Bisector equation:**6x-y-31.5 = 0

**Vector OA = (3; 5) ; |OA| = 5.831**

**Vector OB = (9; 4) ; |OB| = 9.8489**

**Scalar product OA .OB = 47**

**Angle ∠ AOB = 35°4'25″ = 0.6122 rad**